now assume that a satellite of mass mmm is orbiting the earth at a distance rrr from the center of the earth with speed vevev e . a satellite of mass 2m2m2m is orbiting mars, also at a distance rrr from the center of mars, with a speed vmvmv m . what is the ratio tmte

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21-10-2022
Physics

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now assume that a satellite of mass mmm is orbiting the earth at a distance rrr from the center of the earth with speed vevev e . a satellite of mass 2m2m2m is orbiting mars, also at a distance rrr from the center of mars, with a speed vmvmv m . what is the ratio tmte

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aditmarkas98 aditmarkas98 · Answer 1 · 2022-10-25T07:54:38-04:00

The ratio between centripetal force of satellite b and satellite a is 2vm²/ ve².

We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is

Fc = m . v²/R

where Fc is the centripetal force, m is mass, v is velocity and R is the radius.

From the question, we know that

ma = m

mb = 2m

va = ve

vb = vm

ra = rb = r

Find the centripetal force ratio

Fcb / Fca = (mb . vb²/Rb) / (ma . va²/Ra)

Fcb / Fca = (2m . vm²/r) / (m . ve²/r)

Fcb / Fca = 2 . vm²/ ve²

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