the distribution of the number of text messages young adults send per day is approximately normal, with a mean of 128 messages and a standard deviation of 30 messages. based on the distribution, what is the percentage of young adults send fewer than 218 text messages?



Answer :

The percentage of young adults who send fewer than 218 text messages is 99.87%.

For a normally distributed set of data, given the mean and standard deviation, the probability can be determined by solving the z-score and using the z-table.

First, solve for the z-score using the formula below.

z-score = (x – μ) / σ

where x = individual data value = 218

μ = mean = 128

σ = standard deviation = 30

z-score = (218 - 128) / 30

z-score = 90 / 30

z-score = 3

Find the probability that corresponds to the z-score in the z-table. (see attached images)

z-score = 3

probability = 0.9987

To get the percentage, multiply the probability by 100.

percentage = probability x 100

percentage = 0.9987 x 100

percentage = 99.87%

Learn more about probability here: brainly.com/question/26822684

#SPJ4

View image jcmacahia7
View image jcmacahia7