a mouse of mass 27.0 g falls 200 m down a vertical mine shaft and lands at the bottom with a speed of 8.1 m/s. during its fall, how much work (in j) is done on the mouse by air resistance?



Answer :

Work is done on the mouse by air resistance 25.574 Joule.

Work is done every time a force moves something over a displacement. you can calculate the electricity transferred, or paintings done, by using multiplying the force via the gap moved in the course of the force. strength transferred = work achieved = pressure x distance moved within the direction of the pressure.

Work to be accomplished, a force must be exerted and there must be motion or displacement in the route of the pressure. The work done by way of a force appearing on an object is the same as the significance of the pressure accelerated by way of the space moved within the route of the force.

given,

mass = 27.0 g = 0.027 kg

Height H = 200 m

initial speed u = 0 m/s

final speed V = 8.1 m/s

force = mg

        = 0.027 × 9.8

         = 0.2646 N

1/2mu² + mgh = mgh + 1/2mv²

0 + 0.027×9.8 ×100 = 0 + 1/2×0.027× (8.1)² + air reesistance

initial energy = 26.46 J

final energy = 0.886 J

air resistance = 26.46 J - 0.886 J

                        = 25.574 Joule

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