a rock of mass m is released from rest above an airless spherical planet of mass m and radius r. the rock is released from a height r above the surface of the planet (a distance 2r from the center of the planet). what is the correct expression for the final kinetic energy of the rock just before it hits the surface of the planet?



Answer :

E1 = [tex]E_{f}[/tex]

[tex]\frac{-GMM}{2R}[/tex] = [tex]\frac{-GMM}{R}[/tex] + [tex]\frac{1}{2} mv^{2}[/tex]

= [tex]\frac{GMM}{2R}[/tex] = [tex]\frac{1}{2} mv^{2}[/tex]

V = [tex]\sqrt{GM/R[/tex]

By the law of conservation of energy, the initial potential energy, and the final kinetic energy are equal. When an object hits the ground, its kinetic energy is converted into heat and sound energy. Energy from motion is called kinetic energy. object in motion.

Both vertical and horizontal movement has kinetic energy. Kinetic energy depends on the mass and velocity of the object. The basic reason for the existence of halves in the kinetic energy formula actually comes from special relativity from a more complete version of the kinetic energy formula. Briefly, this ½mv2 kinetic energy formula can be viewed as an approximation of special relativity.

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