Answer :
Animal was buried 4821 years ago.
The properties of radiocarbon, a radioactive isotope of carbon, can be used to determine an object's age using radiocarbon dating, which is also known as carbon dating or carbon-14 dating.
55% Carbon-14 is left in the skull.
If A₀ was the original amount of Carbon, the amount of Carbon that is remaining will be 55% of A₀ which equals 0.55A₀
Using the given equation:
[tex]A = A_{O} e^{-0.000124t} \\\\0.55A_{O} = A_{O}e^{-0.000124t} \\\\0.55 = e^{-0.000124t} \\\\ln(0.55) = ln( e^{-0.000124t} )\\\\ln(0.55) = -0.000124t * ln(e) \\\\ln(0.55) = -0.000124t\\\\t = \frac{ln(0.55)}{-0.000124t} \\\\t = 4821[/tex]
hence, option D is correct, the animal was buried 4821 years ago.
Scientists found an animal skull during an excavation and tested the amount of carbon-14 left in it. They found that 55 percent of the carbon-14 in the skull remained. How many years ago was the animal buried? Round your answer to nearest whole number. (Hint: A = A0e-0.000124t.)
A) 443,548 years
B) 362,903 years
C) 6,439 years
D) 4,821 years
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