3. a sociologist wishes to estimate the percentage of u.s. citizens living in poverty. what sample size should be obtained if she wishes the estimate to be within 2% points (the error) with 99% confidence if she uses the year 2000 estimate of 11.8% poverty obtained from the census?



Answer :

The sample size is 1727 points for given data . Sample size is defined as the number of observations used to determine estimates for a given population. Sample size was drawn from the population .

In this question we want to find the sample size and so let's, look at the formula that is given by, the value at over 2, divided by a margin of error, whole squared times p into 1 minus p.

N= ( Z ₐ / E)² p (1-p)

In this case , Z --> Z-Score

E --> error value

P --> estimated proportion or if given standard deviations

Given that, estimate error is 2% that is margin (E) = 2% = 2/100 =0.02

Now, what we have is our confidence level and our made error, so our estimate has been given us 2 percent or confidence level is 99 percent. Now, let's get our Z values, so we use alpha(a) to find out. For alpha value 1 minus 0.99 , we get 0.01. now we are going to be 0.01 divide by 2 and get 0.005 . So, the corresponding value of Z ₀.₀₀₅ is 2.576 . The only value of p is 11.8% (year 2000 estimate ) of what is required for getting an answer

= 118/1000= 0.118

Finally, we put all these values into formula of sample size , i.e.,

N= ( 2.576 / 0.02)² (0.118 )(1- 0.118) = 1726.56 1727

Our sample size is , 1727 point.

To learn more about Sample Size , refer:

https://brainly.com/question/15901889

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