Answer :
The distance travelled due east during the trip is 875.831 meters.
The distance due west is 6.44 km (6440m) and the velocity due west is 2.6m/s. The velocity due east is 0.465m/s.
We know,
Average velocity = Total displacement/Total time
It is given that, the total average velocity is 0.465m/s.
If distance in west is W and the distance in east is E, then the displacement D is,
D = √((6440)²+(E)²)
The time T₁ in west,
T₁ = 6440/2.6 seconds
Time time T₂ in east,
T₂ = E/0.465
The total time T is,
T = T₁ + T₂
T = 6440/2.6 + E/0.465
So, putting all the values now,
Average velocity = D/T
1.37 = √((6440)²+(E)²)/(6440/2.6 + E/0.465)
On solving it further,
We get,
E = 875.831 meters.
So, the distance in east is 875.831 meters.
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