The speed of the aircraft with a narrow strip heater attached = 370.97 m/s
The distance of the strip heater attached to the wing from the leading
edge, x = 0.01 m
Heat flux, q = 300 W/m²
The temperature difference between the heater and surrounding air,
ΔT = 1°C
The properties of the air are
The density of air, ρ = 1 kg/m³
Specific heat at constant pressure, CP = 1 kJ /kg K
Thermal conductivity, k = 0.02 W/mk
Viscosity, ν = 1.5 x 10⁻⁵ m²/s
Dynamic viscosity,
μ = ρ.ν
= 1 x 1.5 x 10⁻⁵
= 1.5 x 10⁻⁵ N s / m²
Prandtl number,
[tex]\displaystyle P_r =\frac{\mu. CP}{k}[/tex]
= 1.5 x 10⁻⁵ x 1 x 10³ / 0.02
= 0.75
Heat flux,
q = hₓ ΔT
300 = hₓ x 1
hₓ = 300 W / m² C
So, the local Nusselt number is
[tex]\displaystyle Nu_x = 0.332 Re_x^{1/2} P_r^{1/3}[/tex]
[tex]\displaystyle \frac{h_x.x}{K} = 0.332 \frac{v.x}{\nu}^{1/2}P_r^{1/3}[/tex]
where v is the velocity of the aircraft
[tex]\displaystyle\frac{300 * 0.01}{0.02} = 0.332 \left( \frac{v*0.01}{1.5 * 10^{-5}}\right)^{1/2} (0.75)^{1/3][/tex]
By further simplifying, we get
150 = 0.332 x 0.9085 x 25.82 x [tex]v^{1/2}[/tex]
v = 370.97 m/s
Therefore, the speed of the aircraft is 370.97 m/s
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