It is not reasonable to use a normal model for the sampling distribution of the sample because the data doesn't meet the success or failure consideration.
The sample has a size of 50 students. The probability that she guesses that about 10% of the class goes is 10%
This will be illustrated as:
1 - p = 1 - 10% = 1 - 0.10 = 0.90
np = 50 × 0.1 = 5. This implies the number of successes.
In this case, the number of successes is less than 10. This is because 5 is less than 10. Therefore, the data doesn't meet the condition.
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