the altitude (i.e., height) of a triangle is increasing at a rate of 3.5 cm/minute while the area of the triangle is increasing at a rate of 4.5 square cm/minute. at what rate is the base of the triangle changing when the altitude is 7.5 centimeters and the area is 87 square centimeters?



Answer :

The rate at which the base of the triangle is changing is equal to,

dB = -6.3 cm/minutes.

From the data given in the question.

The rate of increase in the area of the triangle, dA = 4.5 cm/minute

The rate of increase in the altitude of the triangle, dH = 3.5 cm/minute

The Area of the triangle, A = 87 square centimeters

The altitude of the triangle, H = 7.5 centimeters

The equation for the area of a triangle is equal to

A = 0.5×B×H

Plug in A and H to solve for B at that point:

87 = 0.5×B×7.5

B = 23.2

Differentiate the equation for the area of a triangle to find the rate of change of the area of a triangle (dA):

dA = 0.5× dB× H + 0.5×B × dH.

Plug in known variables to solve for the rate of change of the base dB

dA = 0.5 × dB × H + 0.5 × B × dH

4.5 = 0.5 × dB × 7.5 + 0.5 × 23.2 × 3.5

The rate at which the base of the triangle is changing is equal to,

dB = -6.3 cm/minutes.

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