Answer :
The average intensity of the wave 1 is 9 times the average intensity of the wave 2.
When a electromagnetic wave moves, it carries electric as well as magnetic energy in itself.
The energy of the EM waves is by the equal contribution of both the waves.
It is provided, that wave 1 has electric field E that is three times the maximum electric energy E' of the wave 2.
So, we can say,
E/E' = 3
We know,
The intensity of the wave is given by,
I = 1/2eE²c
Where,
I is the intensity of the wave,
e is a permittivity of free space,
E is the strength of the wave,
c is the speed of light
Now, intensity of the wave 1,
I1 = 1/2eE1²c
For wave 2,
I2 = 1/2eE²c
Now, dividing both the intensity,
I1/I2 = E1²/E2²
We know,
E/E' = 3
So,
I1/I2 = 9
I1 = 9I2
So, we can say,
The intensity of wave 1 is 9 times the intensity of wave 2.
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