The value of the Acceleration at the given speed of 262 m/s will be 0.245 m / s²
Throughout time, the velocity is shifting. In actuality, the velocity is changing by a fixed rate of 10 m/s every second. An object is considered to be accelerating if its velocity is changing; it has acceleration.
Given that:
Mass of car = 2 Tonnes = 2000 kg.
Wheel's power transfer = Efficiency * b.P.
Power = 0.9 * 57000
Therefore, Power = 51300 W
Wheel's angular velocity = (2[tex]\pi[/tex]N / 60) * (1 / rear-axle ratio)
Angular Velocity = (2[tex]\pi[/tex] * 4000) / 60 * (1 / 4.4)
Therefore, Angular Velocity = 95.15 rad / sec
Wheel:
Power = Torque * Angular Velocity
P = F * Tyre Radius * W
⇒ 51300 = F * 0.33 * 95.15
F = 51300 / (0.33 * 95.15)
F = 51300 / 31.4
Therefore, Force = 1633.76 (by the engine)
Resistance:
Rolling Resistance (Fr) = 180 N/tonne * 2 = 360 N
F₁ = 360N
Gradient Resistance:
tanθ = 1 / 25
θ = 2.2906°
Fg = mg * sinθ
Fg = 2000 * 9.84 * sin (2.2906)
Fg = 783.37 N
Acceleration (a):
Net force = Mass * Acceleration
F - (Fr + Fg) = 2000 * a
1633.76 - (360 + 783.37) = 2000 * a
a = 490.39 / 2000
Therefore, Acceleration = 0.245 m / s²
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