two power lines, each 300 m in length, run parallel to each other with a separation of 23 cm . part a if the lines carry parallel currents of 130 a , what is the magnitude of the magnetic force each exerts on the other? express your answer using two significant figures.



Answer :

The magnitude of the magnetic force each exerts on the other is 4.41 N.

The magnitude of the magnetic force depends on the current through the wire, the length of the wire, and the radius of separation. It can be written as

F = μ₀ . I1 . I2 . L / (2π . a)

where F is a magnetic force, μ₀ is vacuum permeability (4π x 10¯⁷ H/m), I1 and I2 is current through the wire, L is the length of the wire and a is the radius of the wire.

From the question above, the given parameters are

L = 300 m

a = 23 cm = 0.23 m

I1 = I2 = 130 A

By substituting the parameters, we can calculate the magnetic force

F = μ₀ . I1 . I2 . L / (2π . a)

F = 4π x 10¯⁷ . 130 . 130 . 300 / (2π . 0.23)

F = 4.41 N

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