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There are two spinners. one spinner has three equally sized sectors that are numbered 1, 2, and 4. the second spinner has four equally sized sectors that are labeled a, b, c, and d. each spinner is spun once. how many outcomes do not show c? responses 4 4, 6 6, 7 7, 9



Answer :

The number of outcomes that do not show c is calculated to be 9 if each spinner is spun once.

The three possible outcomes of the first spinner are 1,2 and 4 and the possible outcomes of the second spinner are a,b,c and d; so if the two spinners are spun together, the possible outcome will be:

a1, a2, a4

b1, b2, b4

c1, c2, c4

d1, d2, d4

Therefore, there are a total of 12 possible outcomes, and 3 out of these possible outcomes show c. Now the outcomes that do not show c can be calculated by subtraction as follows;

Outcome not showing c = Total outcomes - Outcomes showing c

Outcome not showing c = 12 - 3

Outcome not showing c = 9

Therefore, 9 outcomes do not show c if each spinner is spun once.

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Answer: 6

Step-by-step explanation:

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