Answered

if the work required to stretch a spring 3 ft beyond its natural length is 15 ft-lb, how much work (in ft-lb) is needed to stretch it 18 in. beyond its natural length? give your answer in decimal form.



Answer :

ayune

The amount of work needed to stretch the spring 18 in. from its natural position is 3.75  ft-lb.

According to the Hooke's Law, the work done on the spring is:

W = 1/2. k . x²

Where:

k = spring constant

x = displacement.

Notice that the work done is directly proportional to x².

Hence,

W₁ : W₂  = x₁² : x₂²

Parameters given:

W₁ = 15 ft-lb

x₁ = 3 ft

x₂ = 18 in. = 1.5 ft

Plug the above parameters into the ratio equation:

15 : W₂  = 3² : (1.5)²

W₂ = (1.5)² . 15 /  3² = 15/4 = 3.75  ft-lb

Learn more about Hooke's Law here:

https://brainly.com/question/24086534

#SPJ4

Other Questions