an object undergoing simple harmonic motion has an amplitude of if the maximum velocity of the object is what is the object's angular frequency? an object undergoing simple harmonic motion has an amplitude of if the maximum velocity of the object is what is the object's angular frequency? 6.5 rad/s



Answer :

the acceleration is maximum at the peak position and kinetic energy is connected with the mean position.

the object which is performing a simple harmonic motion because the acceleration is directly proportional to displacement that the direction is opposite side the formula is given by

F= -K X

K is the spring constant  

because the amplitude means the maximum displacement

the maximum velocity means that the that is proportional to the angular frequency  and the relation is given by

V=rW

V is the velocity

r is the radius

W is the angular frequency that the SI unit is rad/s.

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ayune

If an object undergoing simple harmonic motion with amplitude 2.3 m and velocity 15 m/s maximum, then its angular frequency is 6.52 rad/s.

Missing data from the question:

- the amplitude is 2.3 m

- the maximum velocity of the object is 15 m/s

The equation for the velocity of a simple harmonic motion is given by:

v = A. ω. cos(ωt)

Where:

ω = angular frequency

A = amplitude

Parameters given:

A = 2.3 m

v = 15  m/s

Let's take t = 0, hence,

v = A. ω. cos(0) = A . ω

15 = 2.3 ω

ω = 15/2.3 = 6.52 rad/s

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