a ten-loop coil having an area of 0.23 m2 and a very large resistance is in a 0.047-t uniform magnetic field oriented so that the maximum flux goes through the coil. the coil is then rotated, so the flux goes to zero in 0.34 s. what is the magnitude of the emf induced in the coil during the 0.34 s?



Answer :

The magnitude of electromotive force is 0.32 volts.

We need to know about the electromotive force of induction to solve this problem. The emf induction appears when there is any change in magnetic flux. The magnitude of emf can be determined by

ε = N dΦ / dt

where N is coil turns, ε is electromotive force, dΦ is change in magnetic flux and dt is time interval.

From the question above, the parameters given are

B = 0.047 T

dt = 0.34 s

N = 10

A = 0.23 m²

Find the change in magnetic flux

dΦ = (B . A)

dΦ = ( 0.047 . 0.23 )

dΦ = 0.01081 Tm²

By substituting the given parameters, we can calculate electromotive force

ε = N . dΦ / dt

ε = 10 . 0.01081 / 0.34

ε = 0.32 volt

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