the large blade of a helicopter is rotating in a horizontal circle. the length of the blade is 7.99 m, measured from its tip to the center of the circle. find the ratio of the centripetal acceleration at the end of the blade to that which exists at a point located 6.16 m from the center of the circle.

Question

21-10-2022
Physics

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the large blade of a helicopter is rotating in a horizontal circle. the length of the blade is 7.99 m, measured from its tip to the center of the circle. find the ratio of the centripetal acceleration at the end of the blade to that which exists at a point located 6.16 m from the center of the circle.

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PNaik PNaik · Answer 1 · 2022-10-28T04:17:20-04:00

The ratio of the centripetal acceleration at the end of the blade to that which exists at a point located 6.16 m from the centre of the circle: 1.29

Centripetal acceleration is given by :

a = ω2R

where,

ω is the angular speed

R is the distance of the point from the centre

Let the point at the tip be A and that at distance 6.16 m from centre be B

Distance of point A from centre (RA) = 7.99 m

Distance of point B from centre (RB) = 6.16 m

Centripetal acceleration at A (aA) = ω2RA = 7.99ω2

Centripetal acceleration at B (aB) = ω2RB = 6.16ω2

The ratio (aA/aB) = 7.99/6.16 = 1.29

What is centripetal acceleration ?

centripetal acceleration is defined as the motion characteristic of an object moving along a circular path. Any object moving in a circle whose acceleration vector points towards the centre of that circle is called centripetal acceleration. You must have seen various examples of medium acceleration in your daily life. When you drive a car around a circle, your car experiences an average acceleration, and the average acceleration is also observed by a satellite orbiting the Earth. Middle means towards the centre.

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