Answer :

AnjaliP102

8.33 x 10²v .

The potential difference at which proton fall is :   = 8.33 x 10²v .

What is potential difference?

  • The work done in moving a unit of positive electric charge from one point to another is defined as potential difference.
  • Electric potential is the work done per unit charge to bring a charge from infinity to a point in an electric field, whereas electric potential difference is the potential developed while moving a charge from one point in the field to another.

Here,

The potential difference is as follows:

Energy change, [tex]e^{v}[/tex] = 1/2 m(v2² - v1²)

By substituting,

1 . 602 x 10 ⁻¹⁹ = 1/2 x 1.67 x 10 ⁻²⁷( 5² - 3²) x 10 ¹⁰

v x 1.602 x 10⁻¹⁹ = 0.835 x 10⁻¹⁷ x 16

v = ( 0.835 x 10⁻¹⁷ x 16 ) / 1.602 x 10⁻¹⁹

  = 0.835 x 10²x16 / 1.602

  = 13.36 x 10² / 1.602

  = 8.33 x 10²v

So the potential difference is : 8.33 x 10²v .

To learn more about potential difference refer to :

https://brainly.com/question/24142403

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