Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.



Answer :

Wave 1's intensity is nine times greater than Wave 2's. An electromagnetic wave carries both magnetic and electric energy when it moves.

What is electromagnetic waves?

An electromagnetic wave carries both magnetic and electric energy when it moves. Both waves contribute equally to the energy of electromagnetic waves. It is assumed that wave 1 has an electric field E that is three times greater than wave 2's maximal electric energy E'.

Thus, we can state:

E/E' = 3

We are aware,

The wave's intensity is determined by,

I = 1/2eE²c

Where,

I represents the wave's power,

e is a free space permittivity,

E represents the wave's energy.

The speed of light is c.

the strength of wave 1 right now

I1 = 1/2eE1²c

second wave

I2 = 1/2eE²c

Currently, dividing the two intensities,

I1/I2 = E1²/E2²

We are aware,

E/E' = 3

So,

I1/I2 = 9

I1 = 9I2

Thus, we can state:

Wave 1's intensity is nine times greater than Wave 2's.

To learn more about electromagnetic waves refer to:

https://brainly.com/question/25847009

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