the population of a town grows at a rate proportional to the population present at time t. the initial population of 500 increases by 15% in 10 years. what will be the pop ulation in 30 years? how fast is the population growing at t 30?



Answer :

Using the differential equation, the population after 30 years is 760.44.

What is meant by differential equation?

  • In mathematics, a differential equation is a relationship between the derivatives of one or more unknown functions.
  • Applications frequently involve a function that represents a physical quantity, derivatives that show the rates at a differential equation that forms a relationship between the three, and a function that represents how those values change.
  • A differential equation is one that has one or more functions and their derivatives.
  • The derivatives of a function define how quickly it changes at a given location.
  • It is frequently used in disciplines including physics, engineering, biology, and others.

The population P after t years obeys the differential equation:

  • dP / dt = kP

Where P(0) = 500 is the initial condition and k is a positive constant.

  • ∫ 1/P dP = ∫ kdt
  • ln |P| = kt + C
  • |P| = e^ce^kt

Using P(0) = 500 gives 500 = Ae⁰.

  • A = 500.
  • Thus, P = 500e^kt

Furthermore,

  • P(10) = 500 × 115% = 575sO
  • 575 = 500e^10k
  • e^10k = 1.15
  • 10 k = ln (1.15)
  • k = In(1.15)/10 ≈ 0.0140
  • Therefore, P = 500e^0.014t.

The population after 30 years is:

  • P = 500e^0.014(30) = 760.44

Therefore, using the differential equation, the population after 30 years is 760.44.

To learn more about differential equations refer to:

brainly.com/question/1164377

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