Answer :
If an elevator in a building starts with five passengers and stops at 7 floors and if each passenger is equally likely to get off at any floor and all the passengers leave independently of each other, then the probability that no two passengers gets off at the same floor will be 0.15.
As per the question statement, an elevator in a building starts with five passengers and stops at 7 floors where each passenger is equally likely to get off at any floor and all the passengers leave independently of each other.
We are required to calculate the probability that no two passengers gets off at the same floor.
Here, since repetition is not allowed,
That is, the total number of ways for 5 passengers are to be assigned to seven floors but no two passengers on the same floor
= 7P5 = [(7!)/(7 - 2)!] = [(7!)/(2!)] = (7 * 6 * 5 * 4 * 3) = 2520
And, the total number of ways to assign 5 passengers to 7 floors, with repetition being allowed will be
= (7)⁵ = 16807.
Therefore, the probability that no two passengers gets off at the same floor will be = (2520/16807) = 0.14993 ≈ 0.15
- Probability: It is that branch of Mathematics which deals with the numerical descriptions concerning the extent to which an event is likely to occur, or how likely it is for a proposition to be true, and is measured by the ratio of the favorable cases to the whole number of cases possible.
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