Answer :
The object's maximum height during projectile motion is 78.4 m.
We need to know about the projectile motion to solve this problem. The projectile motion is known as parabolic motion and the velocity is divided by 2 axes.
vox = vo cosA
voy = vo sinA
where vox is initial velocity of x axis, voy is initial velocity of y axis, vo is initial velocity and A is the angle.
The total time taken during projectile motion is
t = 2(voy)/g
where t is total time and g is the gravitational acceleration (9.8 m/s²)
The maximum height also can be found using this formula
ymax = voy² / 2g
where ymax is the maximum height
From the question above, the given parameters are
A = 30⁰
t = 8 s
Find the initial velocity of y axis
t = 2(voy)/g
8 = 2 . voy / 9.8
voy = 39.2 m/s
Find the maximum object's height
ymax = voy² / 2g
ymax = 39.2² / 2 . 9.8
ymax = 78.4 m
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