The probability that the box contains exactly one defective motor.
P(X=1)=0.5225
This is further explained below.
Generally, This follows a Poisson distribution and will be solved using:
[tex]P(X=x)=\frac{e^{-u} u^x}{x !}[/tex]
Where
u = Expected number of occurrences, and it is calculated as:
u=n p
u=60 * 4%
u=60 * 0.04
u=2.4
In conclusion,
[tex]P(X=x)=\frac{e^{-u} u^x}{x !}[/tex]
Therefore
[tex]P(X=1)=\frac{e^{-2.4} 2.4^2}{2 !}[/tex]
P(X=1)=0.5225
Read more about Poisson distribution
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