The equation for the line that contains the point (5,-3)and is parallel to the line y = 4x +2 is obtained using the point-slope form of the line as y=4x-23.
How can a line that passes through a point be found to be parallel to another line?
Use the point's coordinates for (a, b) in the point-slope form to get a line that passes through the point and is parallel to a line: y - b= m (x -a). Simply enter the slope of the previous line for m.
A point (5,-3) and a line y = 4x +2 are given.
Find the slope of the given equation of the line.
On comparison of the given equation of the line with the standard equation of the line, y=mx+c
m=4
Plug the given point and the slope in the point-slope form of the line.
y-(-3)=4(x -5)
y+3=4x-20
y=4x-23
So, the required equation of the line is y=4x-23
To know more about the relation of the point-slope form:
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