Answer :
The force on the output piston to lift a car is 17 ×10⁴N
The push or pull on a mass-containing item changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
We are given that,
The input area of the piston = A₁ = 0.0580m²
The output area of the piston = A₂ = 0.680m²
The lift a car weighing = F₁ = 1.45× 10⁴N
Therefore , the input force on the piston can be calculated by the formula,
F₁/A₁= F₂/A₂
( 1.45× 10⁴N)/(0.0580m²) =F₂ /( 0.680m²)
F₂ = ( 1.45× 10⁴N)/(0.0580m²) ×( 0.680m²)
F₂ = 17 ×10⁴N
Thus, the output effort of the piston on the car would be 17 ×10⁴N.
To know more about force
https://brainly.com/question/17177301
#SPJ1