Answer :
Answer:
153
Step-by-step explanation:
Hello! Unsure if this is a proper question but I can sure try!
Let's start with the logic of it:
793:
To start with this one, one digit is right and is in the right place. From this step, we can't really infer anything.
725:
One digit is right but in the wrong place. Now we can do something here. There is another digit here that's correct but in the wrong place. We can eliminate 7 entirely from both 725 and 793 as they are in the same position and cannot be in the right and wrong place at the same time.
317:
Two digits are right but in the wrong places. Since we eliminated 7, the two right digits are 3 and 1, just in the wrong spots. At this point, we still need to figure out one more digit so we can't infer their positions just yet.
849:
All digits are wrong. This only affects 793, which removes 9. From here on out, 3 is the correct digit in the right place.
491:
One digit right but in the wrong place. From here, the rule from 849 applies here, meaning we can rule out 9 and 4, leaving us with 1.
From here, it gets a bit tricky. Since 3 is in the correct place. From 725, we have already ruled 7 out, leaving us with 2 and 5. But since we already know 3 is in the last place, it means 5 must be moved to the middle digit in order for 725's statement to be true. Meaning 2 is ruled out.
Finally, the only digit we are left with is 1 as for the rule of 317 and 491.
Making the answer 153.
Let me know if that is correct or wrong and do help me understand if it was wrong!
