The magnitude and location of the resultant of the distributed load is given as
[tex]\bar{x}=3.4545 \mathrm{~m} \quad$[/tex]
This is further explained below.
What is the resultant force?
Generally, In the fields of physics and engineering, a resultant force is a single force and related torque that is created by combining a system of forces and torques operating on a rigid body by vector addition. This process yields the single force and associated torque.
[tex]$\sum F_y=0$F_R=\frac{1}{2} \times(600+1600) \times 6=6600 \mathrm{~N}$\\\\$\sum M_2=0$[/tex]
[tex]$F_R \times \bar{x}=(600 \times 6) \times\left(\frac{6}{2}\right)+(0.5 \times(1600-600) \times 6) \times\left(\frac{6 \times 2}{3}\right)\\\\$$6600 \bar{x}=10800+12000$\\\\$\bar{x}=3.4545 \mathrm{~m} \quad$[/tex]
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