a locomotive of mass 1.1 \times 10^51.1×10 ​5 ​​ kg pulls behind it two train cars, connected one after the other, each with mass 8.1\times 10^48.1×10 ​4 ​​ kg. the entire train begins to accelerate at 0.50.5m/s^2 ​2 ​​ .



Answer :

The pulling force exerted by the locomotive of mass 1.1 * [tex]10^{5}[/tex] kg on the first train car of mass 8.1 * [tex]10^{4}[/tex] kg is 81 KN

F = m a

F = Force

m = Mass

a = Acceleration

Mass of each car = 8.1 * [tex]10^{4}[/tex] kg

Since the locomotive has to pull 2 cars,

m = 16.2 * [tex]10^{4}[/tex] kg

a = 0.5 m / s²

F = 16.2 * [tex]10^{4}[/tex] * 0.5

F = 8.1 * [tex]10^{4}[/tex] N

F = 81 KN

This formula used to solve the problem is derived from Newton's second law of motion. It states that the force is the rate of change in momentum. It can also be written as,

F = dp / dt

Therefore, the pulling force exerted by the locomotive on the first car is 81 KN

To know more about Newton's second law of motion

https://brainly.com/question/13447525

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