The probability for at least one white gumball is 0.196
Consider the following:
First jar:100 whites, 25 green
Total=100+25
=125 gumball
P(White)=100/125=0.8
Second jar:50 whites, 150 blue
Total=50+150
=200 gumballs
P(White)=50/200=0.25
Third jar:500 whites, 10 red
Total=500+10
=510
P(White)=500/500=0.98
Now, probability for at least one white is
=P(white in jar 1)*P(white in jar 2)*P(white in jar 3)
=0.8*0.25*0.98
=0.196
Learn more about probabilities here:
https://brainly.com/question/2239055
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