if test scores for an exam were normally distributed with a mean of 75 and a standard deviation of 5, find the probability that a randomly selected student scored less than 82.



Answer :

the probability that a randomly selected student scored less than 82.

Then the value is  P( X< 82)=0.9192

From the question we are told that

The sample size is  n  =  24

The mean is    =75

The standard deviation is  =5

Generally the  probability that a randomly chosen student scored is less than 82 is mathematically represented as

P( X < 82) = P ( Z< 82-75/5)

                =P(Z <1.4)

                =0.9192

From the z table  the area under the normal curve corresponding to  1.4 is  0.9192

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