the coefficient of kinetic friction between the ramp and the lower box is 0.441, and the coefficient of static friction between the two boxes is 0.834.

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14-10-2022
Physics

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the coefficient of kinetic friction between the ramp and the lower box is 0.441, and the coefficient of static friction between the two boxes is 0.834.

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charithran8975 charithran8975 · Answer 1 · 2022-10-17T10:09:17-04:00

The greatest static resistance between the upper and lower block is f1max = f 1max = s m 1g = 0.6×2×10 = 12N.

According to Newton's second law of motion, an object's net force must equal the sum of its mass and the acceleration it experiences. In the direction of the net force is where acceleration is moving.

The force of action and reaction between two bodies is equal in magnitude but opposite in direction, according to Newton's third law of motion. The highest frictional force that prevents slippage on a surface is known as the limiting friction force.

The highest static resistance between the lower block and the ground is

f2max

=μ s (m 1 +m 2 )g=0.6(2+2)10

=24N

Assumedly, both blocks move to the right at the same speed.

Consequently, (m 1 + m 2 )a = T- μk (m1 + m2)g

or 4a = T - 0.4(2+2)10

or a = T-16 / 4

for upper block, f1 = 2a = T - 16 / 2

For just sliding, f1 = f1max

or T - 16 / 2 = 12

or T - 16 = 24 => T = 40N

The complete question is:

You are lowering two boxes, one on top of the other, down the ramp by pulling on a rope parallel to the surface of the ramp. Both boxes move together at a constant speed of 15.0 cm/s. The coefﬁcient of kinetic friction between the ramp and the lower box is 0.441, and the coefﬁcient of static friction between the two boxes is 0.834. (a) What force do you need to exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?

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