Answer :
The initial resistance of one resistor r in ohms in series combination is 28.5 Ω.
The resistance depends on the used combination. The resistor combination can be combined in 2 ways which are series combination and parallel. In series combination, the resistance will be added up for each resistor. It can be written as
R = R1 + R2
where R is total resistance, R1 and R2 are the series combination of resistors.
From the question above, the given parameters are
R2 = 9 Ω
I1 = 8.4 A
I2 = 6.384 A
Hence, the current ratio of the initial and final condition is
I1 / I2 = V /R1 / V/(R1 + R2)
8.4 / 6.384 = (R1+R2) / R1
8.4 R1 = 6.384 R1 + 57.456
2.016R1 = 57.456
R1 = 28.5 Ω
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