a human expedition lands on an exoplanet. one of the explorers is able to jump a maximum distance of 18.0 m with an initial speed of 2.60 m/s. find the gravitational acceleration on the surface of the exoplanet. assume the planet has a negligible atmosphere. (enter the magnitude in m/s2.)



Answer :

The gravitational acceleration on the surface of the exoplanet is 0.188 m/s².

Gravitational acceleration has an important role in uniform motion. Uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration (gravitational acceleration), t is time and s is displacement.

From the question above, we know that

h = 18 m

vo = 2.6 m/s

In this case, the final velocity should be zero. Hence,

vt² = vo² + 2a . s

vt² = vo² - 2g . h

0² = 2.6² - 2.g . 18

36g = 6.76

g = 0.188 m/s²

Find more on gravitational acceleration at: https://brainly.com/question/19050897

#SPJ4

Other Questions