chloeg3620 chloeg3620

14-10-2022
Physics

Answered

you have a motor with a shaft diameter of 25 mm from which you have hung a weight of 1.1 kg on a thin wire. (assume that the mass of the wire mass is very small compared to that of the weight.) what is the torque on the motor’s shaft?

Answer :

aditmarkas98 aditmarkas98

18-10-2022

The torque on the motor's shaft is 1.375 Nm.

We need to know about torque to solve this problem. Torque is the rotational equivalent of linear force. It can be determined as

τ = F x r

where τ is torque, F is perpendicular force and r is radius.

From the question above, the parameter given are

m = 1.1 kg

d = 25 cm

r = 12.5 cm

Convert radius to meter

r = 12.5 cm

r = 12.5 x 10¯² m = 0.125 m

Find the weight

W = m . g

W = 1.1 . 10

W = 11 N

By substituting the parameters, we get

τ = F x r

τ = 11 x 0.125

τ = 1.375 Nm

Hence, the moment applied is 1.375 Nm

Find more on torque at: https://brainly.com/question/14839816

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