Answer :
Between these two charges, there is an electric field with a magnitude and direction of 10.8 x 105 N/C along AB.
In this issue, we must charge the fee. Twenty micro colums make up Q 1, and eight micro coulons make up Q 2. There is a 20 centimeter gap between these two charges. At point p, which is the intersection of the two charges, we must determine the net electric field. The electric field at point p points away from the charge because of the positive charge. He, let's assume that the electric field is even and that it is caused by the second charge, electric field point along the charge: q 2- and that is the electric field e 2.
The net electric field at point p is now equal to e 1 plus 2 and is represented by the symbol a. Consider the direction away from Question 1 as positive; hence, the direction to the right is a positive direction. The electric field owing to eq, 1 equals the column, constant k times, k 1 over 0.5 times r square, and similarly for eq, 2, where q, 1 and q 2 are the absolute magnitude of the charge, the net electric field at point p equals p over 0.5 r square 0.5 r square times.
The net electric field at point at the midpoint between the 2 charges, equals 2.52 times 10 to the 7 newtons co coulan and the direction will be towards the negative charge towards the minus 8 coulomb judge micro cholum charge. The sum of the absolute magnitude of the 2 charges and the electric field at point p equals 9 times 10 to the 9 newton meter square per column square over 0.5 times 0.2 meter square times, 20 plus 8 times 10 to the minus 6 couul Thus, at the halfway point between the t charges, this will be the net electric field.
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