an ice skater rotating around a vertical axis decreases in angular velocity from 500°/s to 60°/s in 7.6 seconds. find the angular acceleration in rad/s^2.

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14-10-2022
Physics

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an ice skater rotating around a vertical axis decreases in angular velocity from 500°/s to 60°/s in 7.6 seconds. find the angular acceleration in rad/s^2.

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aditmarkas98 aditmarkas98 · Answer 1 · 2022-10-19T07:33:51-04:00

The angular acceleration of an ice skater is -57.89 ⁰/s².

We need to know about angular acceleration to solve this problem. The angular acceleration can be defined as how many angular velocity change in second. It can be written as

a = Δώ / t

where a is angular acceleration, Δώ is change in angular velocity and t is interval time.

From the question above, the parameters given are

ώo = 500 ⁰/s

ώt = 60 ⁰/s

t = 7.6 s

By substituting the given parameters, we can calculate the angular acceleration

a = Δώ / t

a = (ώt - ώo) / t

a = (60 - 500) / 7.6

a = -440 / 7.6

a = -57.89 ⁰/s²

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