a block is given an initial velocity of 5.00 m/s up a frictionless incline of angle 20 degrees. the magnitude of the block’s acceleration is 2.5 m/????2 while it is on the ramp. how far up the incline does the block get before sliding down again?



Answer :

The block will incline up with projectile motion until 0.085 m before sliding down.

We need to know about the projectile motion to solve this problem. The projectile motion is known as parabolic motion and the velocity is divided by 2 axes.

vox = vo cosA

voy = vo sinA

where vox is initial velocity of x axis, voy is initial velocity of y axis, vo is initial velocity and A is the angle.

From the question above, the given parameters are

vo = 5 m/s

A = 20⁰

By using the uniform motion, where vty = 0 m/s. Hence,

vty² = voy² - 2gh

0 = 5.sinA - 2 . 10 . h

20h = 5 . sin20⁰

h = 1/4 . 0.34

h = 0.085 m

Find more on projectile motion at: https://brainly.com/question/3329648

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