particle a has a mass m and a speed v, while particle b has a mass 2m and a speed 2v. what is the ratio of the kinetic energy of particle b to the kinetic energy of particle a?



Answer :

The ratio of the kinetic energy of particle b of mass 2m and a speed 2v to the kinetic energy of particle a of mass m and a speed v is 8 : 1

K = 1 / 2 m v²

K = Kinetic energy

m = Mass

v = Velocity

Let kinetic energy of particle a be K1 and kinetic energy of particle b be K2.

For particle a,

K1 = 1 / 2 m v²

For particle b,

m = 2m

v = 2v

K2 = 1 / 2 ( 2 m ) ( 2 v )²

K2 = 4 m v²

The ratio of the kinetic energy of particle b to the kinetic energy of particle a,

K2 / K1 = ( 4 m v² ) / ( 1 / 2 m v² )

K2 / K1 = 8 / 1

Therefore, the ratio of kinetic energy of particle b to the kinetic energy of particle a is 8 : 1

To know more about kinetic energy

https://brainly.com/question/999862

#SPJ1