a capacitor is charged to a potential of 12.0 vv and is then connected to a voltmeter having an internal resistance of 3.40 mωmω. after a time of 4.00 ss the voltmeter reads 3.5 vv.



Answer :

a. capacitance of circuit is C= 0.849 micro farad & b.  time constant of the circuit is t=2.89 sec.

A component or circuit's capacitance is its capacity to accumulate and store electrical charge as a type of energy. Energy-storing devices known as capacitors come in a variety of sizes and forms. A property of an electric conductor, or group of conductors, known as capacitance is determined by how much separated electric charge can be held on it for each unit change in electrical potential. A store of electrical energy is also implied by capacitance. A potential difference between two initially uncharged conductors is created if electrical charge is transferred between them, causing both to become equally charged (one positively, the other negatively). The capacitance C is defined as the product of the charge density q on each conductor and the potential difference V between them, or C = q/V. Only if the charge is kept constant will capacitance drop as potential increases. Less potential difference equals higher capacitance, according to the equation.

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