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Finding the dimensions of a rectangle given its perimeter and a...
The length of a rectangle is five times its width.
If the perimeter of the rectangle is 120 in, find its length and width.
length: 111
width: in
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Answer :

semsee45

Answer:

Width = 10 in

Length = 50 in

Step-by-step explanation:

Define the variables

  • Let x be the width of the rectangle.
  • If the length is five times its width, then the length of the rectangle is 5x.

Given the perimeter is 120 in:

[tex]\begin{aligned}\textsf{Perimeter of a rectangle} & = 2(\sf width + length)\\120 & = 2(x + 5x)\\120 & = 2(6x)\\120 & = 12x\\\dfrac{12x}{12}&=\dfrac{120}{12}\\\implies x&=10\end{aligned}[/tex]

Solution:

  • Width = 10 in
  • Length = 5 × 10 in = 50 in

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