men versus women: the average 20- to 29-year-old man is 69.9 inches tall, with a standard deviation of 3.0 inches, while the average 20- to 29-year-old woman is 64.1 inches tall, with standard deviation of 3.8 inches. a. find the z scores for a 67-inch- man and a 62-inch woman.



Answer :

The z-scores for a 67-inch- man and a 62-inch woman are -0.9667 and -0.5526, respectively.

The z-score is a numerical measurement used in statistics to determine the sample data value's relationship to the mean of a group of values, measured in terms of standard deviation from the mean. It is measured as the difference of the sample data value and the sample mean over the standard deviation, such that

z-score = (x – μ) / σ

where x = sample data value

μ = mean

σ = standard deviation

For a 67-inch- man, use the formula to solve for the z-score.

x = 67

μ = 69.9

σ = 3.0

z-score = (x – μ) / σ

z-score = (67 - 69.9) / 3.0

z-score = -0.9667

Do the same for a 62-inch- man, use the formula to solve for the z-score.

x = 62

μ = 64.1

σ = 3.8

z-score = (x – μ) / σ

z-score = (62 - 64.1) / 3.8

z-score = -0.5526

Learn more about z-score here: brainly.com/question/17489087

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