The co ordinates of the point B is (12, 12)
Given,
The co ordinates:
Point C = (6, 9)
Point A = (4, 8)
Point B = (x, y)
AC : CB(m : n) = 1 : 3
We have to find the co ordinates of point B.
Lets use the formula to find the coordinates of point C.
C = 1 / (m + n) × (mx₂ + nx₁, my₂ + ny₁)
Where,
C = (6, 9)
m = 1
n = 3
x₁ = 4
x₂ = x
y₁ = 8
y₂ = y
So,
(6, 9) = 1 / (1 + 3) × ((1 × x) + (3 × 4), (1 × y) + (3 × 8))
(6, 9) = 1/4 × (x + 12, y + 24)
(6 × 4, 9 × 4) = (x + 12, y + 24)
(24, 36) = (x + 12, y + 24)
Lets evaluate:
x + 12 = 24 and y + 24 = 36
Solve for x,
x + 12 = 24
Add -12 to both sides
x + 12 - 12 = 24 - 12
We get,
x = 12
Now solve for y,
y + 24 = 36
Add -24 to both sides
y + 24 - 24 = 36 - 24
We get,
y = 12
That is, the co ordinates of the point B is (12, 12)
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