The area of each square in the image below is 25 square units.
1) What is the perimeter of the figure?
2) How can you rearrange the squares (so that sides of the squares line up) to create a figure...
(a) with the same perimeter?

The area of each square in the image below is 25 square units 1 What is the perimeter of the figure 2 How can you rearrange the squares so that sides of the sq class=


Answer :

The perimeter of square is 115.

What is a perimeter of square?

Perimeter of square = Sum of the lengths of 4 sides. = side + side + side + side. = 4 × side. Therefore, the perimeter of Square = 4s units.

Perimeter of figure = sum of all outer side of figure

Given that,

Area of each square = 25 square units

We know that, area of square = [tex]a^{2}[/tex]

Where, a is the side of the square.

25 =  [tex]a^{2}[/tex]

a = [tex]\sqrt{25}[/tex]

a = 5 unit

Then, perimeter of figure = sum of all boundary sides of the figure

                                          = 5+5+5+5+..........

                                          = 115

Hence, The perimeter of square is 115.

To learn more about square from the given link:

https://brainly.com/question/25092270

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Answer:

  1) 120 units

  2) see attachment

Step-by-step explanation:

Given a figure composed of 21 squares that each have an area of 25 square units, you want to know (1) the perimeter of the figure, and (2) how to rearrange it to have the same perimeter, but with sides that line up.

(1) Perimeter

The perimeter is the sum of the lengths of the sides that form the boundary of the figure. The boundary consists of ...

  • 6 top-side horizontal edges
  • 6 bottom-side horizontal edges
  • 6 left-side vertical edges
  • 6 right-side vertical edges

for a total of 6·4 = 24 edges of the squares shown.

Each of the squares shown has an area of A = s² = 25 units², so a side length of s = √(25 units²) = 5 units.

The perimeter is the length of 24 of these edges, so is ...

  perimeter = 24 × 5 units = 120 units

(2) Rearrangement

The 21 squares shown in the figure can only be rearranged into rectangles that are 21 × 1 squares or 7 × 3 squares. These will have perimeters of 44 or 20 edges, respectively. Hence, it is not possible to have "sides of the squares line up" in a rectangle with the same perimeter.

The attached figure is the next best thing. It shows a 6 × 4 rectangle with three squares removed (to keep the total at 21). The number of horizontal and vertical edges total 24, as required to keep the same perimeter.

View image sqdancefan