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2. A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s2. Determine the time for the feather to fall to the surface of the moon.



Answer :

The total time taken by the feather to fall to the surface of moon will be 1.29 seconds.

Given is a feather dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s².

State second equation of motion.

The second equation of motion is -

S = ut + 1/2 at²

We can write -

[S] = 1.4 m

[a] = 1.67 m/s²

[u] = 0 m/s

Using the second equation of motion -

S = ut + 1/2 at²

S = 1/2 at²

1.4 = 1/2 x 1.67 x t²

1.4 = 0.835 x t²

t = 1.29 seconds

Therefore, the total time taken by the feather to fall to the surface of moon will be 1.29 seconds.

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