Answer :
In the context of momentum, leftward momentum should equal rightward momentum. This is chapter 1.2. That ought to be 1.8 kg into two meters per second. Finally, this we equals 1.8 when two is divided by 1.2, which is 3.0 meters per second.
There are four different challenges in the example given. The first one refers to the initial ball's mass. This is assumed assuming that each person is equivalent to 1.5 telegrams and the second pool ball's mass. M2 is that This also equates to an initial speed of 2.3 kg.
The first pool ball is moving at 25 meters per second, whereas the second pool ball was initially at rest. The first ball ultimately comes to rest after colliding with the second pool ball, becoming zero, and we must determine the second ball's final speed. To do this, we will apply the principle of conservation of linear momentum, which states that the linear momentum of both balls remains constant.
The balls before to impact indicate M 1. We have a total of two from one plus M. That corresponds to the ultimate momentum and one we F plus M. This is 1.5 kg in 2 25 m per second plus zero, and we need to plug in all the known variables. For the first ball after coalition because it comes to rest Plus 2.3 kg Into VF two, it will be zero for the second ball is equal to here.
Lasting Speed of Second Pool Ball. Therefore, it works out to be 2.3 kg into VF 2. And canceling this kilogram here, it is equivalent to 37.5 kilogram meters per second.
The answer to the first problem supplied to him now in the second problem, problem number two, mass of the bullet Small, is determined to be equivalent to 16.3 meters per second for the second pool ball. The bullet's speed is five kilograms per second, and the block in which it is implanted has a mass of 0.005 kilograms.
The bullet designated as Small B has an initial speed of 500 m/s and an overall speed of both. The block and bullet that are absent. We need to locate it.
Since the blocks were released earlier and the spring was also handled, their initial momentum was zero. Eventually, they began to move in the other direction. hence where momentum is concerned, leftward momentum should equal rightward momentum. This is chapter 1.2. That ought to be 1.8 kg into two meters per second. Finally, this we equals 1.8 till two divided by 1.2 results in a speed of 3.0 meters per second.
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