Answered

a large air-filled 0.211-kg plastic ball is thrown up into the air with an initial speed of 10.9 m/s. at a height of 3.49 m, the ball's speed is 3.03 m/s. what fraction of its original energy has been lost to air friction?



Answer :

Initial energy equals (M/2)*Vo2 = 12.80 J.

At 4.7 m and V = 5 m/s, total energy equals (M/2)

*5^2 + M*g*4.7 = 1.25 + 4.61 J

a portion of the energy in a ball LOST = (12.80-5.86)/12.80 \s= 0.542

We are informed that a plastic ball with a mass of 0.1 kg is tossed into the air as an example of energy conservation. It starts off at a height of three meters and a speed of 10 meters per second. Now moving at three meters per second. We are interested in learning how much of its initial energy has been lost through friction. We now know that the total mechanical energy is constant for an isolated system. Thus, the change in gravitational potential energy descends to you along with the change in kinetic energy data K. additionally the data on N. G. Lost to air friction Zero is equal to E. F. Keep in mind that the gravitational potential energy you I is zero at the beginning.

It follows that either their energy changes or that the energy lost to friction belt E. F. is equal to minus daughter. Kay, without a doubt, which is without uh-huh. Mm. V squared divided by the starting speed is the final speed. M. G. H. plus V not squared Additionally, the ball's initial energy is entirely kinetic. Since this is a half-squared north, the lost energy delta E. F. is the proportion of the original energy that is reflected and lost.

This therefore equals half of M. Squared into the not minus V squared into the not minus to G. H. multiplied by half. squared M Vinod Thus, this fraction becomes the square of the starting speed. We not squared minus the final speed squared square V squared minus twice the acceleration brought on by gravity, G times the height of the ball. H centered over Vinod. Therefore, if we enter our numbers here, this becomes 10 m/s squared times three m/s squared times two, or 9.81 m/km2 times. three meters tall times 10 meters per second squared.

As a result, 32 321 the amount of energy that is lost when there is an uncertainty about e f over e I This is the percentage that is lost due to air friction, or 32.1 percent.

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