Answer :
The de Broglie wavelength for a particle== 0.92 ×10⁻³⁴m.
de broglie wavelength is the wavelength associated with particle of mass m moving with velocity v.
p= h/ λ
where, p -is the momentum of the atom;
h- Planck's constant - 6.626×10⁻³⁴ m²kg s⁻¹
λ- wavelength;
Momentum can be expressed as
p=m×v
where , m is the mass of the particle;
v - the speed of the particle.
so,
λ = h/(m×v)
= ( 6.626×10⁻³⁴ m²kg s⁻¹)/(1.2kg × 6.0 m/s)
= (6.626×10⁻³⁴ m²kg s⁻¹)/7.2
= 0.92 ×10⁻³⁴ m
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