Answer :
The minimum radius of the circle is 5249m
The 76kg pilot's effective weight at the bottom of the circle is 5214N
The pilot's effective weight at the top the circle is 3724N
Here's the complete question:
a jet pilot takes his aircraft in a vertical loop.
a) if the jet is moving at a speed of 2000 km/h at the lowest point of the loop, determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.0g's
b) calculate also the 76kg pilot's effective weight ( the force with which the seat pushes up on him) at the bottom of the circle.
c) calculate the pilot's effective weight at the top the circle. (Assume the same speed.)
a) To determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.0g's.
v =2000 km/h
v = 2000/3.6 m/s
v = 555.6 m/s
centripetal acceleration, a
a = v²/r
Therefore
6g = v²/r
r = v²/(6g)
r =555.6²/(6*9.8)
r = 5249 m
b) The 76kg pilot's effective weight at the bottom of the circle
76*(6g + g) = 76*7*9.8 = 5214 N
c) The pilot's effective weight at the top the circle.
76*(6g-g) = 76*5*9.8 = 3724 N
Learn more about centripetal acceleration from:
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