The moment of inertia of the rod with respect to a parallel axis through one end of the rod is Ml^2/3
To calculate inertia, according to the parallel axis theorem:
[tex]I=I_{cm}+Md^{2}[/tex]
Where,
I is the inertia from an axis that is at distance d from the center of mass and Icm is the inertia when the axis passes through the center of mass.
The distance d = l/2
Now to calculate inertia
[tex]I=I_{cm}+Md^{2}[/tex]
[tex]I=\frac{Ml^{2}}{12} + M\frac{1}{2}\\I=\frac{Ml^{2}}{12}+\frac{Ml^{2}}{4}\\I=\frac{Ml^{2}+3Ml^{2}}{12}\\I=\frac{Ml^{2}}{3}[/tex]
The moment of inertia of the rod with respect to a parallel axis through one end of the rod is Ml^2/3.
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